Question

A CIRCULAR PATH WAY HAS TO BE CONSTRUCTED AROUND A CIRCULAR GROUND. IF THE AREAS OF THE OUTER AND INNER CIRCLE ARE 1368 m² AND 616 m² RESPECTIVELY, FIND THE WIDTH AND AREA OF THE PATH

GIVEN:
AREA OF THE OUTER CIRCLE = 1368 m²
AREA IF THE INNER CIRCLE = 616 m²

TO FIND:
AREA OF THE PATH
WIDTH OF THE PATH

SOLUTION:
AREA OF THE PATH =AREA OF THE OUTER CIRCLE -
AREA OF THE INNER CIRCLE

Complete all the next steps and find the answer that should be the width 7m and area 770m

Answer 1

Answer:

Step-by-step explanation:

Area of the outer circle = 1386 m2 πR2 = 1386m2

Area of the inner circle = 616 m2 πr2 = 616m2

Area of the path = Area of outer circle – Area of the inner circle 1386 m2 – 616 m2

Area of the path = 770m2 Also πR2 = 1386 R2  = 1386 × 7 22 1386×722 R2 = 63 x 7 R2 = 9 x 7 x 7 R2 = 32 x 72 R = 3 x 7

Outer Radius R = 21 m

Again πr2 = 616 22 7 227 x r2 = 616 r2 = 28 x 7  

r2 = 4 x 7 x 7

r2 = 22 x 72  r = 2 x 7

 Inner radius r = 14m

 Width of the path = Outer radius – Inner radius  = 21 – 14

Width of the path = 7m