Question

A circular pice of thin wire is converted into a rhombus of side 11cm.find the diameter of the circular peice

Answer 1

Heya,

According to the question,
Side of rhombus = 11cm

As, we know that rhombus have all sides equal

So, perimeter of rhombus = 4×11 = 44cm

As, the circular pice of thin wire is converted into a rhombus.
Therefore,

Circumference of circle = Perimeter of rhombus
so,
Circumference of circle = 44cm

Now,

2πr = 44

=> 2×22/7×r = 44

=> r = 44×7/44

=> r = 7

So, radius of circle = 7 cm

Therefore, diameter of circle = 2×7
= 14 cm

Hope this helps....:)

Answer 2

$\large \bold{ \underline{ \underline{ \sf \: Answer : \: \: \: }}}$

$\to$ Diameter = 14 cm

$\large \bold{ \underline{ \underline{ \sf \: Explaination : \: \: \: }}}$

Given ,

$\to$ Side of rhombus = 11 cm

$\to$ Perimeter of rhombus = 11 × 4 i.e 44 cm

According to the question ,

$\star$Perimeter of rhombus = Circumference of circle

So ,

$\to \sf 44 = π × d \\ \\ \to \sf </p><p></p><p>44 = \frac{22}{7} × d \\ \\ </p><p> \to \sf </p><p>44 × \frac{7}{22} = d \\ \\ </p><p> \to \sf </p><p>d = 14 \: cm$

$\therefore$The diameter of circular piece is 14 cm