A circular piece of thin wire is converted into a rhombus of side 11 cm find the diameter of the circular piece
Answers
Answered by
6
perimeter will remain the same
the perimeter of the Rhombus will be 44 CM
similarly the perimeter of circle will be equal to the perimeter of rhombus
2PiR=44
r=7
diameter=14CM
the perimeter of the Rhombus will be 44 CM
similarly the perimeter of circle will be equal to the perimeter of rhombus
2PiR=44
r=7
diameter=14CM
Answered by
19
hiii!!!
here's ur answer...
perimeter of rhombus=circumference of circle
given the side of the rhombus is 11cm
perimeter of the rhombus=side×4
=11×4
=44cm
therefore circumference of the circle is also 44cm.
=> 2πr=44cm
=> 2×22/7×r=44cm
=> 44/7×r=44cm
=> r=44/1×7/44
=> r=7cm
verification:-
circumference of circle=2πr
=2×22/7×7
=44cm
hence verified
thus the radius is 7cm.
therefore diameter of the circle=7×2
=14cm (as we know diameter is double of radius)
hope this helps..!
here's ur answer...
perimeter of rhombus=circumference of circle
given the side of the rhombus is 11cm
perimeter of the rhombus=side×4
=11×4
=44cm
therefore circumference of the circle is also 44cm.
=> 2πr=44cm
=> 2×22/7×r=44cm
=> 44/7×r=44cm
=> r=44/1×7/44
=> r=7cm
verification:-
circumference of circle=2πr
=2×22/7×7
=44cm
hence verified
thus the radius is 7cm.
therefore diameter of the circle=7×2
=14cm (as we know diameter is double of radius)
hope this helps..!
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