a circular piece of thin wire Is converted into a square of side 6.25 cm. if there is no loss or gain in its length, find the radius of the circular wire
Answers
Answered by
25
side of square= 6.25cm
perimeter of Square = 4 *side
= 6.25*4
=25.00cm
25cm
perimeter of square= circumference of circle
( because of the same wire used in both cases)
circumference of circle= 25cm
![2\pi \times r = 25 \\ 2 \times 22 \div 7 \times r = 25 \\ r = 25 \times 7 \div 2 \times 22 \\ r = 175 \div 4 4 \\ r = 3.97cm(approx) 2\pi \times r = 25 \\ 2 \times 22 \div 7 \times r = 25 \\ r = 25 \times 7 \div 2 \times 22 \\ r = 175 \div 4 4 \\ r = 3.97cm(approx)](https://tex.z-dn.net/?f=2%5Cpi+%5Ctimes+r+%3D+25+%5C%5C+2+%5Ctimes+22+%5Cdiv+7+%5Ctimes+r+%3D+25+%5C%5C+r+%3D+25+%5Ctimes+7+%5Cdiv+2+%5Ctimes+22+%5C%5C+r+%3D+175+%5Cdiv+4+4+%5C%5C+r+%3D+3.97cm%28approx%29)
r= 175*44
r=3.97cm (approx)
perimeter of Square = 4 *side
= 6.25*4
=25.00cm
25cm
perimeter of square= circumference of circle
( because of the same wire used in both cases)
circumference of circle= 25cm
r= 175*44
r=3.97cm (approx)
Similar questions