a circular piece of thin wire is covered into a square of side
11 centimetre if there is no loss or gain its length then radius of circular wire is
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Answered by
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Perimeter of square = circumference of circle
4× side = 2πr
4×11 = 2×22/7 × r. ( Side = 11cm)
44/2 = 22/7×r
22×7/22 = r
7cm =r
Hope it helps...
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4× side = 2πr
4×11 = 2×22/7 × r. ( Side = 11cm)
44/2 = 22/7×r
22×7/22 = r
7cm =r
Hope it helps...
Mark it brainliest plzzzz plzzzz ....if it really helps
aryarajesh2005:
hi
Answered by
0
side (s)=11 cm.
therefore perimeter of a square
=4×s
=4×11
=44 cm.
As there is no loss or gain in its length
Therefore circumference of circle will also be the same
Therefore ,
Circumference (C)
2πr=44
2×22÷7×r=44
44r÷7=44
r÷7=1. ......bcoz 44 of L.H.S. & R.H.S.
cuts
therefore, r=7 cm
therefore perimeter of a square
=4×s
=4×11
=44 cm.
As there is no loss or gain in its length
Therefore circumference of circle will also be the same
Therefore ,
Circumference (C)
2πr=44
2×22÷7×r=44
44r÷7=44
r÷7=1. ......bcoz 44 of L.H.S. & R.H.S.
cuts
therefore, r=7 cm
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