Question

A circular piece of wood with an area of 202 pie cm has a smaller circle cut out from it. the area of the remaining piece is 121 pie cm. find the area of the smaller circle (in the terms of pie) and the radius of the smaller circle

Answer 1

area of outer circle=202πcm
area of remaining piece=121πcm
So,area of inner circle=area of outer circle-area of remaining piece
=(202π-121π)cm
=81πcm
area of inner circle=πr×r

Answer 2

The area of smaller circle is $81 \pi$ and radius of smaller circle is 9 cm

Step-by-step explanation:

Area of remaining piece = Area of big circle - Area of small circle

Area of remaining circle =$121 \pi$

Area of big circle =$202 \pi$

$121 \pi = 202 \pi - \pi r^2 \\121 = 202 -r^2 \\r=\sqrt{202-121}$

r=9

Area of smaller circle =$\pi r^2 = \pi \times 9^2 =81 \pi$

Hence The area of smaller circle is $81 \pi$ and radius of smaller circle is 9 cm

#Learn more:

Find the radius and area of circle if circumference is 31.4 cm and take pie=3.14.

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