Question

A circular pillar of radius 25 cm supports a weight of 484 N. Calculate the pressure exerted on the pillar in Pa.

Answer 1

pressure = force / area of cross section

now,
area of cross section =πr^2

=π(25/100)^2

=π/16 m^2
now ,
pressure = force /CSA
=484N/(π/16)
=484 x 16 x 7/22
=22 x 7 x 16 =2464 N/m^2

Answer 2

Given:
radius= 25cm
1m=100cm
radius=r= 25/100=0.25m
Force = weight =484N
Pressure= Force/ area
As the pillar in this case is circular.
So, area of circle =A= pi*r*r
Therefore , Pressure= F/pi* r*r
P= 484/(3.14×0.25×0.25)
= 484/0.196
=2469.38N/ m2 or Pascals
Therefore, pressure exerted on pillar is 2469.38 N/ m2 or pascals