Question

A circular pipe of diameter 0.5 m carries the discharge of 50 liters/s. The head loss due to friction in pipe is 0.15 m and friction factor for the pipe is given

Answer 1

Given:

A circular pipe of diameter 0.5 m carries the discharge of 50 liters/s. The head loss due to friction in pipe is 0.15 m and friction factor for the pipe is given .

To Find:

Length of the circular pipe?

Solution:

given;

diameter of circular pipe, $d=0.5m$

discharge rate, $Rate =50 l/s$  ⇒ $Q=50mlit/s=50/1000=0.05m^{3}/s$

head loss due to friction=$hf=0.15 m$

Now, firstly find the velocity of flow;

$V=\dfrac{Discharge}{Area}$

$V=\dfrac{Q}{\frac{\pi}{4}d^{2} } \\\\V=\dfrac{0.05}{3.14}*\dfrac{4}{0.5^{2} } \\\\=\dfrac{0.2}{0.785}\\\\=0.254$

therefore, velocity is 0.25 m/s.

let, coefficient of friction be f then,

By, Darcy's formula,

$\[\begin{gathered} hf = \frac{{4 \times f \times L \times {V^2}}}{{d \times 2g}} \hfill \\ 0.15 = \frac{{4 \times f \times L \times {{0.25}^2}}}{{0.5 \times 2 \times 9.8}} \hfill \\ L = \frac{{0.15 \times 2 \times 0.5 \times 9.8}}{{4 \times f \times 0.0625}} \hfill \\ L = \frac{{1.47}}{{0.25f}} \hfill \\ L = \frac{{5.88}}{f} \hfill \\ \end{gathered} \]$

Hence, length of of the circular pipe is given by-

$L=\dfrac{5.88}{f}$

Answer 2

Answer:

ans

Explanation:

xhxochoxhxohhxxzh