Question

A circular pond is 17.5m is diameter. It is surrounded by a 2m wide path. Find the cost of construction the path at the rate pf Rs 25, per msquare.

Answer 1

Answer:

first we find area of path

area of path=pi. {R^2-r^2}

R=17.5/2+2=8.75+2=10.75

r=8.75

now area of path =22/7 x ({10.75)^2-(8.75)^2=22/7 x 2 x 19.5=122.460 m^2

now

cost of constructing path =122.46 x 25

3061.5 Rs