A circular pond is of diameter 17.5m. It is surrounded by 2m wide path. Find the cost of constructing the path at the rate of Rs 25 per square meter(Use π = 3.14).
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15
A circular pond is of diameter 17.5m.
so radius = 17.5/2=8.75m
area of the pond with the path= 22/7×8.75²=240.625
It is surrounded by 2m wide path
so diameter=17.5+4=21.5
so radius=21.5/2=10.75m
area of the pond with the path= 22/7×10.75²=363.196
arae of path =area of the pond with the path-area of the pond with the path
=363.196-240.625
=122.571 m² is the area of path
cost of constructing the path at the rate of Rs 25 per square meter
=122.571 m²×25
=rupees 3064.275
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so radius = 17.5/2=8.75m
area of the pond with the path= 22/7×8.75²=240.625
It is surrounded by 2m wide path
so diameter=17.5+4=21.5
so radius=21.5/2=10.75m
area of the pond with the path= 22/7×10.75²=363.196
arae of path =area of the pond with the path-area of the pond with the path
=363.196-240.625
=122.571 m² is the area of path
cost of constructing the path at the rate of Rs 25 per square meter
=122.571 m²×25
=rupees 3064.275
.pls mark as brainleist
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Answered by
12
Given,
Diameter = 17.5
Radius = 8.75
Area of pond = 22/7 × 8.75 × 8.75
= 240.625
Again it is surrounded by 2m wide path
Therefore diameter = 17.5+2+2 = 21.5
Radius = 10.75
Area of pond along with path
= 22/7×10.75×10.75
= 363.196
Area of path = 363.196 - 240.625
= 122.571
Cost of constructing the path
= 122.571×25
= Rs 3061.50
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