Question

A circular pond is of diameter 17.5m it is surrounded by a 2 m wide path find the cost of constructing a road in this path at rate of 25 per sq meter

Answer 1

Step-by-step explanation:

1750/2cm(d)= 87.5cm(r)

Area of pond=pai × r^2

=22/7 ×87.5^2

=24062.5 sq cm

=240.625 sq m

Area of pond with pathway of 2m

Here R = 87.5+200 cm

=287.5cm

Area of pathway along with pond= pai×287.5^2

=259776.79 sq cm

=2597.7679 sq m

Area of only pathway = 2597.77(approx)-240.63(approx)

=2357.14 sq m= 2357(approx)

Contruction price = 2357×25

=58925 ruppes.

Ruppes 58925 (approx) are required.

Answer 2

To find the area of the path we have to find the outer area and inner area and subtract the both

r₁ = Outer radius = 17.5/2 + 2 = 8.75 + 2 = 10.75

r₂ = Inner radius = 17.5/2 = 8.75

Area of outer circle = πr₁² = π×10.75² = 362.8m²

Area of inner circle = πr₂² = π×8.75² = 240.6m²

Therefore the area of the path = 362.8 - 240.6 = 122.2m²

1m² ------> ₹25

122.2m² ------> 25×122.2 = ₹3,055

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