Math, asked by sabit1453, 1 year ago

A circular pond is of diameter 43 m is surrounded by a 3 m wide path. find yhe cost of constructing the path at the rate of rs 25 per metre square.

Answers

Answered by Einsteindaddy
15
diameter of pond =43metre
radius of pond=43/2=21.5m
radius of circular region with Path =21.5+3=24.5m
Area of bigger circular region =3.14×24.5×24.5
=1884.785
Area of pond =1451.465
Path area=1884.785-1451.465=433.32
cost =433.32×25=10833 rupees
Answered by GulabLachman
2

Given:

(i) The circular pond has a diameter of 43m

(ii) The path around the pond has a width of 3m

(iii) The cost of constructing the path is at a rate of Rs 25/m.

To find:

(i) The total cost of construction.

Solution:

Given, the diameter of the circular pond is 43m.

Radius = Diameter/2 = 43/2 = 21.5m

We know that for a circle of radius r, its area is given as:

A = Пr²

So, for the pool, its area would be:

A = П(21.5)² m²

Taking П as 3.14, we get the area as

A = 1451.47 m²

As the path is 3m wide, the circular figure formed including the path, will have the radius of (21.5+3)m

= 24.5m

Area = П(24.5)² m²

= 1884.79 m²

So, the area of the path only = (1884.79-1451.47) m²

= 433.32 m²

As 1m² costs Rs 25.

So, 433.32 m² will cost = Rs (25*433.32) m²

= Rs 10833

The total cost of construction is Rs 10833.

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