a circular pond is surrounded by a 2 m wide circular path if the outer circumference of the circular path is 44 m find the inner circumference of the circular park also find the area of the path.
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Let R and r be the radius of the outer and inner circle respectively.
We know that the circumference of a circle =2∏r
Given, circumference of outer circle = 44 m
2∏R = 44
2 ×
× R = 44
R = 7 m
R = R – 2 = 7 – 2 = 5 m
Inner circumference = 2 × 3.14 × 5 = 3.14 m
Area of the path = Area of outer circle - area of inner circle
=∏R2 - ∏r2 =∏(R2 - r2)
= 3.14 (72 – 52) = 3.14 × (49 – 25) = 3.14 × 24 = 75.36 m2
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