A circular pond is surrounded by a 2m wide circular path. If the outer circumference of a circular path is 44m. Find the inner circumference of the circular path. Also find area of the path
Answers
The radius of the inner circle is 5 m.
The area of the path is 75.43 m².
Explanation:
The circumference of the outer circle is 44 m.
Circumference = 2πr
∴ 44 = 2×(22/7)×r
⇒ r = (44×7)/(2×22)
⇒ r = 7 m
∴ The radius of the inner circle = (7-2) m
= 5 m.
The area of the outer circle =(πr²)
= (22/7) ×(7)²
= (22 × 7 ×7/7)
= (22×7)
= 154 m².
Similarly, the area of the smaller circle = (22/7)×(5)²
= (22×5×5/7)
= 78.57 m².
∴ The area of the path = (154.00 - 78.57) m²
= 75.43 m²
∴ The area of the path is 75.43 m².
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