a circular pond is surrounded by a 2m wide circular path .if the outer circumference of the circular path is 44 m find the inner circumference of the circular path .also find the area of the path.
Answers
Step-by-step explanation:
Let R be radius of outer circle and r be radius of inner circle.
It has been given that 44m is the circumference of outer circle,
⇒2πR=44m
⇒2×
7
22
×R=44
⇒R=
2×
7
22
44
=
2×22
7×44
=7m
It is given that circular path is 2 m wide.
So, radius of inner circle r=R−2=7−2=5 m
So, inner circumference of path =2πr=2×
7
22
×5=31.42 m
Therefore,
Area of the path = area of outer circle - area of inner circle
⇒π(R
2
−r
2
)
=
7
22
(7
2
−5
2
)=
7
22
×24
=75.43m
2
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Step-by-step explanation:
Given:A circular pond is surrounded by a 2m wide circular path.if the outer circumference of the circular path is 44 m.
To find:Find the inner circumference of the circular path, also find the area of the path.
Solution:
1) Outer radius of path:
Let the outer radius of circular path is R.
So,
Outer radius of circular path is 7 m.
It is given in the question itself that circular path is 2 m wide.
Thus, Inner radius of circular path(Radius of circular pond)r = 7-2= 5 m.
2) Inner circumference of path(Circumference of pond):
3) Area of circular path:
Thus,
Inner circumference of circular path is=31.43 m
Area of path is =75.43 m²
Hope it helps you.
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