a circular pond is surrounded by a 2m wide circular path .if the outer circumference of the circular path is 44 m find the inner circumference of the circular path .also find the area of the path.
Attachments:
Answers
Answered by
4
:-) Here is your answer xD
circumference of outer circle= 2πr
44 = 2 x 22/7 x r
44 x 7/22 = r
therefore, r = 14 m
now the radius of inner circle = outer - 2
= 14- 2
= 12 m
Now, circumference of inner path = 2πr
= 2 x 22/7 x 12
= 75.42 m
Now are of outer circle = πr²
= 22/7 x 14 x 14
= 616 m²
Now area of inner circle= πr²
= 22/7 x 12 x 12
= 452.5 m²
Therefore , are of path = area outer - area inner
= 616 - 452.5
= 163.5 m²
ANSWER = 163.5 m² and 75.42 m
<strong>Mark as brainliest</strong>
circumference of outer circle= 2πr
44 = 2 x 22/7 x r
44 x 7/22 = r
therefore, r = 14 m
now the radius of inner circle = outer - 2
= 14- 2
= 12 m
Now, circumference of inner path = 2πr
= 2 x 22/7 x 12
= 75.42 m
Now are of outer circle = πr²
= 22/7 x 14 x 14
= 616 m²
Now area of inner circle= πr²
= 22/7 x 12 x 12
= 452.5 m²
Therefore , are of path = area outer - area inner
= 616 - 452.5
= 163.5 m²
ANSWER = 163.5 m² and 75.42 m
<strong>Mark as brainliest</strong>
rahul200414:
thank you
Similar questions