Question

A circular racing track has inner circumference 310 m and Outer circumference 618 m find the width of the track

Answer 1

Step-by-step explanation:

the answer is 49 m after subtracting the outer and inner radiuses

Answer 2

Answer:

The width of the track is 49.04m

Step-by-step explanation:

We know that Circumference of a circle =2πr

Therefore For the first inner circumference

310=2π(r1)

$r1 = \frac{310}{2\pi} \\ \\ = \frac{155 \times 7}{22} \\ \\ r1 = 49.31$

Similarly for the second circumference

618=2πr2

$r2 = \frac{618}{2\pi} \\ \\ = \frac{309 \times 7}{22} \\ \\ r2 = 98.35$

Now width of the track can be calculated by the difference of radius.

$r2 - r1 = 98.35 - 49 .31 \\ \\ width = 49.04$

I hope you are clear if not just comment me and mark me as the brainliest.