Question

a circular racing track has inner circumference 528 and Outer circumference 616 M find the width of the track

Answer 1

Answer:

14 m

Step-by-step explanation:

Let the outer radius be R m

Let the inner radius r mOuter circumference=616m

2πR=616m

2×22/7 × R=616

R=(616×7)/44

R=98m

Inner circumference=528m

2πr=528m

2 × 22/7 × r=528

r=(528×7)/44

r=84 m

Width of the track=R-r=98-84=98-84=14m