a circular racing track has inner circumference 528 metre and Outer circumference is 616 M find the width of the track
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first whole circumference=2pir
outer circle=616
616 =2×22/7×r
616×7/2×22=r
616/22=28 ,28/2=14 14×7=98
so whole radius=98
inner circumference=528
528=2×22/7×r
528×7/2×22=r
528/22=24; 24/2=12,12×7=84
now outer circumference rafius - inner circumference radius=98-84=14
track width is 14 m
outer circle=616
616 =2×22/7×r
616×7/2×22=r
616/22=28 ,28/2=14 14×7=98
so whole radius=98
inner circumference=528
528=2×22/7×r
528×7/2×22=r
528/22=24; 24/2=12,12×7=84
now outer circumference rafius - inner circumference radius=98-84=14
track width is 14 m
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