Question

A circular ring 2.4 m in diameter has a charge
density Of &
C/m. Find E at the aenter of the ring.​

Answer 1

minimum 7.9 centimetre

Answer 2

Answer:

Radius =r, So, 2πr= Circumference

Charge density =λ

Total charge =2πr×λ

Electric potential=

r

Kq

=

4πε

0

1

×

(x

2

+r

2

)

1/2

2πrλ

=

2ε

0

(x

2

+r

2

)

1/2

rλ

So, Electric field =

r

V

cosθ

=

2ε

0

(x

2

+r

2

)

1/2

rλ

×

(x

2

+r

2

)

1/2

1

=

2ε

0

(x

2

+r

2

)

1/2

rλ

×

(x

2

+r

2

)

1/2

x

=

2ε

0

(x

2

+r

2

)

3/2

rλx

.