A circular ring 2.4 m in diameter has a charge
density Of &
C/m. Find E at the aenter of the ring.
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minimum 7.9 centimetre
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Answer:
Radius =r, So, 2πr= Circumference
Charge density =λ
Total charge =2πr×λ
Electric potential=
r
Kq
=
4πε
0
1
×
(x
2
+r
2
)
1/2
2πrλ
=
2ε
0
(x
2
+r
2
)
1/2
rλ
So, Electric field =
r
V
cosθ
=
2ε
0
(x
2
+r
2
)
1/2
rλ
×
(x
2
+r
2
)
1/2
1
=
2ε
0
(x
2
+r
2
)
1/2
rλ
×
(x
2
+r
2
)
1/2
x
=
2ε
0
(x
2
+r
2
)
3/2
rλx
.
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