Question

A circular ring is rotated about its own axis with an angular velocity 70π rad/s , its moment of inertia is 0.04 kgm^2, then its angular momentum will be​

Answer 1

Explanation:

Evaporation is a type of vaporization that occurs on the surface of a liquid as it changes into the gas phase.[1] The surrounding gas must not be saturated with the evaporating substance. When the molecules of the liquid collide, they transfer energy to each other based on how they collide with each other. When a molecule near the surface absorbs enough energy to overcome the vapor pressure, it will escape and enter the surrounding air as a gas.[2] When evaporation occurs, the energy removed from the vaporized liquid will reduce the temperature of the liquid, resulting in evaporative cooling

Answer 2

Answer:

Initial moment inertia of the ring I  

1

​

=MR  

2

   

Final moment of inertia when m mass is attached I  

2

​

=MR  

2

+2mR  

2

 

Now using the angular momentum conservation  

I  

1

​

ω=I  

2

​

ω  

2

​

⇒ω  

2

​

=  

M+2m

Mω

​