Question

a circular ring of diameters 40 com and mass 1 kg is rotating about an axis normal to the plane and passing through the center with frequency of 10 revolutions per sec calculate the angular momentum about its axis of rotation

Answer 1

angular momentum = Iω = 1/2Mr^2ω = 1/2.1.(20/100)^2.10= 5.1/25 = 1/5 kg m^2s^-1