Question

a circular ring of mass M and radius R is roll on a horizontal surface with speed v. what is its kinetic energy ?

Answer 1

hey here's your answer__________
I(circular ring)=MR^2
w(omega-angular velocity)=v/R
---kinetic energy =1/2(I)(w^2)
---1/2Mv^2

Answer 2

Answer:Mv^2

K.E. 1/2Iw^2 + 1/2Mv^2

1/2MR^2v^2/R^2+1/2Mv^2

Mv^2

Explanation: