Physics, asked by yogitamalode14, 9 months ago

A circular ring of mass m and radius r rolls down on inclined plane of height h. When it
reaches the bottom of the plane, its angular velocity is w and its rotational kinetic energy
is K. Then

(A) w=1/r(√gh)

(B) w=1/2r(√gh)

(C) k = mgh
(D) k =1/4(mgh)

Answers

Answered by vaibhavchoudhary790

2

Answer:

(B)w=1/2r(gh) it is the rught answer

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