Question

A circular ring of radius R starts rolling on the horizontal surface and complete a half rotation as shown below.the displacement of the point p is

Answer 1

Answer:

Explanation:

=> Here, A circular ring of radius R starts rolling on the horizontal surface and complete a half rotation

=>Thus,  Circumference of circle = 2πR

But circle rotate at 180°. So It is πR

Diameter of the circle = 2R

=> According to Pythagoras theorem:

PP' = √(πR)² +  (2R)²

= √(π²R²) + (2)²R²

= √π²R² + 4R²

= R√π²+4

Thus, the displacement of the point p is R√π²+4.

Answer 2

Answer:

Explanation:

Solution is in the pic attached below.

Hope it helps!