A circular road of equal width exists surrounding a circular park. The differences between the inner and outer circumferences of the road is 44 m. If the area of the road be 1386 sq m what is the area of the park?
perform the sum..
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answer: 2464
Step-by-step explanation:
let R and r be the radius of outer and inner circular park.
2pi R-2pi (r) = 44
R-r=7 ......(1)
also,
pi R² - pi r²=1386
R²- r² = 441
(R+r)R-r = 441
R+r= 63 {from . 1} ......(2)
from 1 and 2.. we get
R= 35 and r= 28
area of park is inner area only we dont consider outer area so,
area of park =pi r²= 22/7 * (28 )² = 2464 m²
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