Question

a circular road runs around a circular ground if the differences between the circumference of the outer circle and inner circle is 66 metres find the width of the road

Answer 1

Given

• A circular road runs around a circular ground.
• Differences b/w the circumference of the outer circle and inner circle is 66 metres

Explanation

✯Firstly, We have to find the Circumference of the Outer circle and then Circumference of the inner circle.

Let the Outer radius be R and Inner radius be r

✯At the time of comparing, we can denote their difference as Given in the Question.

✯For this We apply Formula :-

$\maltese {\pmb{\boxed{\sf{ 2πR-2πr }}}} \\ \\ \colon\implies{\sf{ 2π(R-r) }} \\ \\ \\ \colon\implies{\sf{ 66 = 2π(R-r) }} \\ \\ \\ \colon\implies{\sf{ 66 = 2 \times \dfrac{22}{7} (R-r) }} \\ \\ \\ \colon\implies{\sf{ \dfrac{ \cancel{66} \times 7}{2 \times \cancel{22} } = (R-r) }} \\ \\ \\ \colon\implies{\sf{ \dfrac{3 \times 7}{2} = (R-r) }} \\ \\ \\ \colon\implies{\sf{ \cancel{ \dfrac{21}{2} } = (R-r) }} \\ \\ \\ \colon\implies{\sf{ (R-r) = 10.5 }}$

Hence,

✯ ${\underline{\sf{ The \ width \ of \ the \ Road \ is \ 10.5 \ metres. }}}$