Question

A circular road runs around a circular ground.if the radius of the ground is 3.5m and the difference between the circumference of the outer circle and inner circle is 88m, then the area of the road

Answer 1

outer circumference-inner circumference=2π(R-r)

=88=2π(3.5-r)

88×7/2×22=3.5-r

14-3.5=r

10.5

Answer 2

The area of the road is 924 sq.m.

Step-by-step explanation:

Radius of ground = 3.5 m  

Circumference of ground =$2 \pi r = 2 \times \frac{22}{7} \times 3.5=22$

A circular road runs around a circular ground.

Let the radius of circular road be R  

We are given that the difference between the circumference of the outer circle and inner circle is 88m

So,  $2 \pi R - 22= 88$

$2 \times \frac{22}{7} \times R =110$

$R = \frac{110 \times 7}{2 \times 22}$

R=17.5 m  

Area of road = Outer area - Inner area  

Area of road =$\pi R^2 - \pi r^2$

Area of road =  $\frac{22}{7}(17.5^2 - 3.5^2}$

Area of road =924 sq.m.

Hence the area of the road is 924 sq.m.

#Learn more:

A circular road runs around a circular garden if the circumferences of the outer circle and the inner circle are 110 m &88m find the width of the road

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