A circular road runs round a circular ground if the difference betweenthe circumference of the outer circle and inner circle is 66m find width of road?
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Difference of circumference=66m
2pi(R-r) =66m
(R-r)=66/2pi
=66/(2 x 22/7)=21/2m
here (R-r) is width of road=10.5m
2pi(R-r) =66m
(R-r)=66/2pi
=66/(2 x 22/7)=21/2m
here (R-r) is width of road=10.5m
ss490080p3w45y:
sorry but plz clear it
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