A circular road runs round a circular ground. If the differences between the circumferences of the outer circle and inner circle is 66 metres, find the width of the road?
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Answer:
Let radius of outer circle = R
and radius of inner circle = r
ATQ 2π−2πr=66
2π(R−r)=66
R−r=662π=66×72×22=212
width=10.5m
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A circular road runs around a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is ... A) 10.5 metres.
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