Question

A circular sedimentation tank fitted with standard mechanical sludge removal equipment is to handle 3 MLD of raw water. If the detention period of the tank is 4 hours and the depth of the tank is 3 m. What should be the diameter of the tank?

Answer 1

What type of q is this? Loool

Answer 2

Answer:

16.03 Meters

Explanation:

Given

Quantity of the raw water to be treated per day = 3 * (10^6) Litres

Quantity of the raw water to be treated per day during detention period =

[3*(10^6)*4] / 24

= 625000 Litres

=625 cu.meters

The capacity of the circular tank of depth D and height H is given by

Volume = d^2[0.011d + 0.785H]

625= d^2[0.011d+0.785*3]

625=d^2[0.011d+2.255]

625=0.011*d^3+2.255*d^2

0.011*d^3+2.255*d^2-625=0

On Solving the equation we get d=16.03 m

Hence diameter of the tank = 16.03m

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