Question

A circular sell of depth 7m and radius 1.5m dug. Calculate the cost of cementing the inner surface at rate of rupess 5 per sqm




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Answer 1

Answer:

here is your answer,

Step-by

inner surface area = C.S.A OF SELL + AREA OF BASE

now, C.S.A = 2$\pi$rh=2*3.14*1.5*7 = 66 sq. cm

also, area of base = $\pi$$r^{2}$=3.14*$1.5^{2}$ = 7.065

so, INNER AREA = 66 + 7.065 sq. cm

                           = 73.065 sq.cm

COST = 5 * 73.065= 365.325 rupees

Answer 2

Answer:

$\large\boxed{\sf{Rs.\:365.325}}$

Step-by-step Explanation:

Given that,

A well is dug such that,

• Radius, r = 1.5 m
• Height, h = 7 m

Now, to find the cost of cementing the inner surface.

Let's find out the curved surface area.

Therefore, we will get,

=> A = 2πrh

=> A = 2 × 22/7 × 1.5 × 7

=> A = 44 × 1.5

=> A = 66 sq. m

Also, area of base,

=> a = πr^2

=> a = 22/7 × (1.5)^2

=> a = 7.065 sq. m

Therefore, total area to be cemented is,

= A + a

= 66 + 7.065

= 73.065 sq. m

Now, Cost of cementing 1 sq. m = ₹ 5

Therefore, cost of cementing the inner surface = ₹ ( 73.065 × 5)

=> Cost = ₹ 365.325

Hence, required cost is ₹ 365.325