Question

A circular shaped portion of radius 0.07 m was removed from a thin circular metal sheet of radius 0.75 m.

(i) Show that the area of the remaining part is (π 0.82 x 0.68.)

Answer 1

Step-by-step explanation:

In bigger circle----R=0.75m

In smaller circle-----r=0.07m

Area of the remaining part/required area=Area of bigger circle-area of smaller circle

Area of bigger circle=πR²

=π ×0.75×0.75

=0.5625π ----------(1)

Area of smaller circle=πr²

=π ×0.07×0.07

=0.0049π -----------(2)

Subtracting (1) from (2) gives us the required area

=0.5625π - 0.0049π

=(0.5625 - 0.0049)π

=(0.5576)π

=(0.82×0.68)π

Answer 2

Answer:

x/2-1/4 = x/3+1/2

x/2 - x/3 = 1/2+1/4

3x-2x/6 = 1+2/4

x/6 = 3/4

4x = 18

x = 18/4 = 4.5

hope helped !