A circular swimming pool has a radius of 15 ft. There is a path all the way around that pool that is three feet wide.What is the circumference of the outer edge of the path around the pool? Use 3.14 for Pi.
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4
Answer:
113.04
Step-by-step explanation:
Radius of pool = 15 ft
Path = 3 ft
Radius of the path and pool = 15 + 3 = 18 ft
Formula = 2πj
Therefore, the circumference of the outer edge of the path around the pool is:.......
2 x 3.14 x 18 ft = 113.04
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3
Answer:
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