A circular target of radius 11 cm consists of an inner circle of radius 5 cm and 3 concentric circles of radii 7 cm, 9 cm and 10 cm dividing the target into 4 regions. If a shot hits the target,find the probabilities of hitting each region. If you shoot the target 121 times, what is your expectation? How will you improve your performance?
Answers
Answer:
1.36 * (10^-83) is the correct answer
Step-by-step explanation:
Probability is the amount of favourable outcomes divided by the total possible outcomes. In our case, it means the area of inner circle (one region) by the total area of the target which consist of other 3 regions.
So,Firstly we will find the area of the entire target.
Formula for the area of circle =^2
TargetCircle=()(11)^2
TargetCircle=121
Now we find the area of the innermost circle using the same formula.
InnerCircle=()(5)^2
InnerCircle=25
Expectation to hit the inner circle
=25/121 ^121
=0.207^121 = 1.36 * 10^-83
The probability of hitting each region.
5cm :
25/121 =0.207
7cm:
49/121 =0.405
9cm:
81/121 =0.669
10cm:
100/121 =0.826
Answer:
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Step-by-step explanation:
Probability is the amount of favourable outcomes divided by the total possible outcomes. In our case, it means the area of inner circle (one region) by the total area of the target which consist of other 3 regions.
So,Firstly we will find the area of the entire target.
Formula for the area of circle =^2
TargetCircle=()(11)^2
TargetCircle=121
Now we find the area of the innermost circle using the same formula.
InnerCircle=()(5)^2
InnerCircle=25
Expectation to hit the inner circle
=25/121 ^121
=0.207^121 = 1.36 * 10^-83
The probability of hitting each region.
5cm :
25/121 =0.207
7cm:
49/121 =0.405
9cm:
81/121 =0.669
10cm:
100/121 =0.826