Question

a circular target of radius 11 cm consists of an inner circle of radius 5 cm and three concentric circles with same centre of radius 7 cm, 9 cm and 10 cm dividing the target into four regions. If a shot hit the target, find the probability of hitting each region. If you shoot the target 121 times, what is your expectation to hit the inner circle

Answer 1

Answer:

1.36 * (10^-83)

Step-by-step explanation:

Probability is the amount of favourable outcomes divided by the total possible outcomes. In our case, it means the area of inner circle (one region) by the total area of the target which consist of other 3 regions.

So,Firstly we will find the area of the entire target.

Formula for the area of circle =^2

TargetCircle=()(11)^2

TargetCircle=121

Now we find the area of the innermost circle using the same formula.

InnerCircle=()(5)^2

InnerCircle=25

Expectation to hit the inner circle

=25/121 ^121

=0.207^121 = 1.36 * 10^-83

The probability of hitting each region.

5cm :

25/121 =0.207

7cm:

49/121 =0.405

9cm:

81/121 =0.669

10cm:

100/121 =0.826

Answer 2

Answer:

ans

Step-by-step explanation:

above