A circular track has a circumference of 2150 m with AB as one of its diameters. A scooter rider moves from A to B along the circular path with a uniform speed of 5 m/s. Find- (a) distance covered by the scooter rider. (b) displacement of the scooter driver. (c) time taken by the scooter rider in reaching from A to B.
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Answer:
Explanation:
taking the value of pi 3.14
circumference = 2*pi*r = 2150
r=1025/pi
r=1025/3.14
distance covered 2r=215000/314
distance is equal to displacement
speed in which distance of 2r was covered 5m/s
Time=2r/5m/s
Time= (2150/3.14)/5
Time= 10750/3.14=1075000/314
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