Question

 A circular track has a circumference of 3140 m with AB as one of its diameter. A scooterist moves from A to B alone the circular path with a uniform speed of 10 m/s. Find

       (a)  distance covered by the scooterist,

       (b)  displacement of the scooterist, and

       (c)  time taken by the scooterist in 

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Answer 1

Explanation:

given that:

circumferrance of circle=3140m

find radius,

2×22/7×r=3140

44/7×r=3140

r=3140×7/44

r=785×7/11

r=499.5m

(a)distance=22/7×r

=22/7×499.5=1569.8m

(b)diplacement = 2×499.5=999m

(c)distance= 1569.5m

speed=10m/s

time = distance/speed

= 1569.5/10

= 156.95 sec

Answer 2

Answer :-

a) 1568.55 m

b) 999.08 m

c) 156.9 s

Given:-

Circumference of track = 3140 m

Uniform speed = 10 m/s

To find :-

 (a)  distance covered by the Scooterist.

 (b)  displacement of the scooterist.

 (c)  time taken by the scooterist in.

Solution :-

Circumference of circle = $2 \pi r$

$3140 = 2 ×\dfrac {22}{7} r$

$r = \dfrac {3140 × 7}{2 × 22}$

$r = 499.54 m$

Now, Distance travelled is equal to half of circumference

$\therefore$$D = \pi r$

$S = \dfrac{314}{100}× 499.54$

$S = 1568.55 m$

2) Displacement covered is equal to the diameter of track

$S = 2r$

$S = 2 × 499.54$

$S = 999.08m$

3) Time taken by scooterist is equal to distance / speed.

$T = \dfrac {S}{V}$

$T = \dfrac {1568.55} {10}$

$T = 156.9 s$