Question

A circular track has a circumference of 3140 m with AB as one of its diameter. A scooterist moves from A to B alone the circular path with a uniform speed of 10 m/s. Find
(a) distance covered by the scooterist,
(b) displacement of the scooterist, and
(c) time taken by the scooterist in reaching from A to B.

Answer 1

Explanation:

$\huge\bf\underline{\red{A}\purple{N}\pink{S}\orange{W}\blue{E}\green{R}}$

Given:-

Circumference = 3140m

Speed = 10 m/s

(A) distance covered by the scooterist.

Distance of scooter = circumference /2

$= \frac{3140}{2} \\ \\ = 1570 \: m$

(B) displacement of the scooterist.

Displacement of the scooter = AB

= circumference /π

$\frac{3140}{3.14} \\ \\ = 100 \: m$

(C) time taken by the scooterist in reaching from A to B.

Time taken = distance /speed

$\frac{1570}{10 } \\ \\ = 157 \ s$

Answer 2

Answer:

$\huge\bold\pink{AnSwEr}$

Circumference=3140m

Speed=10m/s

a) Distance of scooter = circumference / 2

=3140/2

=1570m

b) Displacement of scooter = AB

=circumference/π

=3140/3.14

=1000m

c) Time taken = distance / speed

=1570/10

=157s

Refer daigram in attachment