Question

A circular track has a circumference of 3140m with ab as one of its diameter. a scooterist moves from along the circular path with a uniform speed of 10m/s.find distance covered by the scooterist ,displacement of thescooterist and time taken in reaching from a to b.

Answer 1

Hi friend,

This is your required answer.

Given,

Circumference of circular track=2=3140m

where r=radius of circle

Now according to question,Scooter moves from a to b along the circular path (where ab is diameter).It means scooter completes half a revolution(circumference/2).

So,

Distance travelled=The actual path traversed by scooter=2/2=3140/2=1570 m

Again,

Displacement=The shortest distance travelled by scooter(Final position-Initial position)=Diameter of the circle=2r

Since 2=3140m (here =3.14)

2r=3140/3.14=1000 m.

To calculate the time taken by the scooter in reaching from a to b,we have a formula

Speed=Distance/Time

Time=Distance/Speed=1570/10=157 seconds.

Hope this helps you..☺☺

Answer 2

Answer:

Hi friend,

This is your required answer.

Given,

Circumference of circular track=2=3140m

where r=radius of circle

Now according to question,Scooter moves from a to b along the circular path (where ab is diameter).It means scooter completes half a revolution(circumference/2).

So,

Distance travelled=The actual path traversed by scooter=2/2=3140/2=1570 m

Again,

Displacement=The shortest distance travelled by scooter(Final position-Initial position)=Diameter of the circle=2r

Since 2=3140m (here =3.14)

2r=3140/3.14=1000 m.

To calculate the time taken by the scooter in reaching from a to b,we have a formula

Speed=Distance/Time

Time=Distance/Speed=1570/10=157 seconds.

Hope this helps you..☺☺