A circular track has an inside circumference 528m, if the width of the track is 3.5 m, find the outer circumference
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cir. of inner circle=2×22/7×r
528=2×22/7×r
r=528×7/2×22
r=336
total r=336+3.5
=341.5
cir. of outer circle=2×22/7×r
=2×22/7×341. 5
=50.59
528=2×22/7×r
r=528×7/2×22
r=336
total r=336+3.5
=341.5
cir. of outer circle=2×22/7×r
=2×22/7×341. 5
=50.59
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