Question

A circular track of radius 600 m is tio be designed for cars at an average speed of 180 km/hr. What should be the angle of banking of the track?

Answer 1

no......no....no.....

Answer 2

Answer:

Angle=22.6

Explanation:

v=speed=180 km/h=180×5/18 m/s=50m/s

r=radius

g=10m/s

We know tetha =tan inverse(v^2/rg)

Then tetha=tan inverse(50×50/600×10)

Tetha=tan inverse(5/12)

Tetha=22.6