Question

A circular water fountain 6.6 m in diameter is surrounded by a path of width 1.5 m .What is the area of the path. (Write the answers correct upto two places of decimal)

Answer 1

given,
diameter of the fountain=6.6m
total diameter=diameter of the fountain + 1.5m
=6.6m + 1.5m
=8.1m
radius=8.1m/2 =4.05m

Area= πr²
=3.14×4.05m×4.05m
=51.50385m²

Answer 2

Answer:

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$\blue {⇰Diameter = 6.6m}$

$\sf ⇒\dfrac{6.6}{2} m$

$\sf ⇒3.3m$

$\pink {⇰Area \: of \: the \: fountain \: = \pi d^{2}}$

$\sf ➩\dfrac{22}{7} \times (3.3m {)}^{2}$

$\sf ➩\dfrac{22}{7} \times 3.3m \times 3.3m$

$\sf ➩\dfrac{ \cancel2 \cancel {2}^{11} }{7} \times \dfrac{33}{ \cancel 1 \cancel {0}^{5} } \times \dfrac{33}{10}$

$\sf ➩\dfrac{11979}{350}$

$\sf ➩34.22$

$\orange {⇰Diameter \: of \: bigger \: circle}$

$\sf ➯6.6m + 1.5m + 1.5m$

$\sf ➯9.6m$

$\purple {⇰Radius \: of \: bigger \: circle}$

$\sf ➬\dfrac{ \cancel9. \cancel {6}^{4.8} }{2} m$

$\sf ➬4.8m$

$\sf \red {⇰Area \: of \: bigger \: circle = \pi {r}^{2}}$

$\sf ➾\dfrac{22}{7} \times (4.8m {)}^{2}$

$\sf ➾\dfrac{ \cancel2 \cancel {2}^{11} }{7} \times \dfrac{\cancel4\cancel {8}^{24} }{\cancel1\cancel {0}^{5} } \times \dfrac{48}{ \cancel1\cancel {0}^{5} }</p><p>$

$\sf ➾\dfrac{12672}{175} m$

$\sf ➾72.41m$

$\green {Area \: of \: the \: path = 72 . 41 - 34.22}$

$\sf ➺38.19m$

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