Question

A circular wheel has a radius of 2m. It rolls forward half a revolution on a
horizontal ground. The magnitude of displacement of point of the wheel
initially in contact with the ground is?

Answer 1

Answer:

half revolution of circular wheel on horizontal ground = 6.285 cm

Answer 2

The magnitude of displacement of the point of the wheel initially in contact with the ground is 7.45 m.

Given: A circular wheel has a radius of 2 m. It rolls forward half a revolution on horizontal ground.

To Find: The magnitude of displacement of the point of the wheel initially in contact with the ground.

Solution:

• It is to be noted that we need to find the displacement which is the smallest distance and one point to the other.
• We know that the displacement for half a revolution on a horizontal ground can be given by the formula,

      Displacement = R √( π² + 4 )                                          ...(1)

where R = radius given.

Coming to the numerical,

The radius (R) of the wheel is = 2 m

Putting respective values in (1), we know that,

         Displacement = R √( π² + 4 )    

                                 = 2 × √( (3.14)² + 4 )    

                                 = 7.45 m

Hence, the magnitude of displacement of the point of the wheel initially in contact with the ground is 7.45 m.

#SPJ2