Question

A circular wheel of mass 50 kg and radius 200 mm is rotating at 300 r.p.m find its kinetic energy

Answer 1

Answer:

493.29J

Explanation:

w= 300rpm

w=(300*2*pi)/60   convert rpm into rad/s

w=31.41rad/s

M given 50kg

R given as 200mm convert it in terms of meter

I=0.5* MR^2 (M R squared)

I=0.5*50 * (200*10^-3)^2

I=0.5*50*0.04

I=1 kgm^2

KE=0.5*I*w^2  (w squared)

KE=0.5*1*(31.41)^2

KE=493.29J