Physics, asked by jithinjoseph1911, 11 months ago

A circular wire loop of radius r can withstand a radial force t before breaking. A particle of mass m and charge q is sliding over the wire

Answers

Answered by gauravarduino
4

Explanation:

(The mass m of the ship does not matter.) ... Before the bird does anything is just sitting on the bottom, there is a force down on ...... In the case of a circular orbit of radius R, FT=0 and the centripetal ...

Answered by ravilaccs
0

Answer:

A particle of mass m and charge q is sliding over the wireV=\frac{r}{2 m}\left[q, \sqrt{q^{2} B^{2}+\frac{T m}{r}}\right]

Explanation:

\begin{aligned}&T+q v B=\frac{m v^{2}}{R} \\&\frac{m v^{2}}{R}-q v B-T=0 \\&m v^{2}-v(q B R)-\frac{q T=0}{v=} \\&v=\frac{\gamma}{2 m}\left[\frac{q^{2} B^{2} R^{2}+4 m R 7}{2 m}\right. \\&V B+\sqrt{q^{2} B^{2}+\frac{T m}{Y}}\end{aligned}

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