A circular wire of diameter 10 cm is cut and placed along the circumference of a circle of diameter 1 m. Find the angle subtended by the wire at the center of the circle. pls its urgent.....
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Answered by
42
Length of wire = π x D = 22/7 x 10 = 31.428 cm
This length is equal to the length of the arc of the larger circle diameter = 1 m = 100cm
Length of arc = β/360 x πD (Where β is the angle subtended at the center)
⇒ β/360 x 22/7 x 100 = 31.428
55/63 β = 31.428
β = 31.428 x 63/55 = 36 degrees.
The angle subtended by the wire at the center = 36 degrees
This length is equal to the length of the arc of the larger circle diameter = 1 m = 100cm
Length of arc = β/360 x πD (Where β is the angle subtended at the center)
⇒ β/360 x 22/7 x 100 = 31.428
55/63 β = 31.428
β = 31.428 x 63/55 = 36 degrees.
The angle subtended by the wire at the center = 36 degrees
Answered by
16
Answer:
the answer is π/5
Step-by-step explanation:
Understanding the question: here in the question a wire of radius 5cm is made to cover some part of the periphery of a bigger circle having radius 50cm.
Explanation: the circumference of the smaller circle will be the length of arc (L) for the bigger circle.
so Circumference of smaller circle = 2×π×5 = 10π
now we know that the Radius (R) of the bigger circle is 50 cm.
so α = L ÷ R = 10π ÷ 50 = π/5
Hence the angle subtended by the wire at the centre of the circle is eual to π/5.
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