Question

A circular wire of diameter 154 cm is cut and bent in the form of rectangle whose sides are in the ratio of 6:5 find the 25% of the smallest side of the rectangle

Answer 1

Solution:-

Given:-

Diameter of Circular Wire = 154 cm.

=) Radius = 154/2

=)Radius = 77cm.

Now,

Circumference of a Circle = 2πr

=) Circumference = 2 × 22/7 × 77

=) Circumference = 2 × 22 × 11

=) Circumference = 484 cm.

Given that, A Circular wire is bent in the Form of Rectangle.

Let the length and Width of the Rectangle be 6x and 5x.

Hence,

Circumference of Circular Wire = Perimeter of Rectangle

=) 484 = 2 ( 6x + 5x)

=) 484/2 = 11x

=) 11x = 242

=) x = 22 cm.

Hence,

Length of Rectangle = 6x

=) Length = 6 × 22

=) Length = 132 cm

Width = 5x

=) Width = 5 × 22

=) Width = 110 cm.

Now,

25% of Small side of Rectangle.

=) 25/100 × 110

=) 110/4

=) 27.5