Question

A circular wire of radius 21cm is bent into a shape of a square find the area of a square

Answer 1

Answer:

radius of circular wire = 21

circumference of circular wire = 2πr

2*22/7*21

2*22*3

132cm

now ,

perimeter of square = 132 cm

4a=132 cm

a = 132/4

a= 33 cm

area of square is a*2

2*33

66 sqm

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Answer 2

$\large\underline{\underline{\sf Given:}}$

• Circular wire of radius (r) = 21cm

$\large\underline{\underline{\sf To\:Find:}}$

• Area of square (A) = ?

$\large\underline{\underline{\sf Solution:}}$

${\boxed{\sf Circumference\:of\:Circle = Perimeter \:of\: square}}$

$\large\implies{\sf 2πr=4×side}$

$\large\implies{\sf 2×\frac{22}{7}×21=4×side}$

$\large\implies{\sf 132=4×side}$

$\large\implies{\sf side=33cm}$

As we know :

${\boxed{\sf Area\:of\: Square (A)=(side)^2}}$

$\large\implies{\sf A=(33)^2}$

$\large\implies{\sf A=66cm^2}$

$\large\underline{\underline{\sf Answer:}}$

•°•Area of square is 66cm²