A circular wire of radius 3 cm is cut and
bent so as to lie along the circumference
of a hoop whose radius is 36 cm . Then
the angle in degrees which is subtended
at the centre of hoop is
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Answer:
30°(π/6)
Step-by-step explanation:
Radius of the circular wire =3 cm.
∴ Length of the circular wire = 2π × 3 = 6π cm
[Circumference = 2π r]
Radius of the hoop = 36cm.
Let θ be the angle subtended by the wire at the centre of the hoop. Then,
θ = arc/radius
θ =6π /36= π/6 = 30°
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